![]() Step 6 – Determine the current in various sections, I 1’’, I 2’’ and I 3’’. Step 5 – Now consider the other source E 2 and replace the source E 1 by its internal resistance r 1 as shown in the circuit diagram C. Taking the above example find the current I 1’, I 2’and I 3’. Step 4 – Thus, by activating one source and deactivating the other source find the current in each branch of the network. ![]() Step 3 – If there is a voltage source than short circuit it and if there is a current source then just open circuit it. If its internal resistance is not given, then it is taken as zero and the source is short-circuited. Step 2 – In the circuit diagram B shown above, consider the source E 1 and replace the other source E 2 by its internal resistance. Step 1 – Take only one independent source of voltage or current and deactivate the other sources. Steps for Solving network by Superposition TheoremĬonsidering the circuit diagram A, let us see the various steps to solve the superposition theorem: The direction of the current should be taken care of while finding the current in the various branches. i 1’’, i 2’’, i 3’’ flowing in the circuit diagram shown below:Īnd the value of the current i 3’’ will be calculated by the equation shown below:Īs per the superposition theorem, the value of current i 1, i 2, i 3 is now calculated as: Now, activating the voltage source V 2 and deactivating the voltage source V 1 by short-circuiting it, find the various currents, i.e. ![]() The difference between the above two equations gives the value of the current i3’
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |